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本文小编为大家详细介绍“怎么实现python画圆功能”，内容详细，步骤清晰，细节处理妥当，希望这篇“怎么实现python画圆功能”文章能帮助大家解决疑惑，下面跟着小编的思路慢慢深入，一起来学习新知识吧。
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效果：
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.patches import Polygon
import matplotlib.patches as mpatches
fig = plt.figure(figsize = (16,8))
ax = fig.gca()
ax.set_xlim(-5,18)
ax.set_ylim(-5,8)
alpha = np.linspace(-np.pi,np.pi,30)
t = np.linspace(-np.pi,np.pi,100)
def ppp(nc , na , c , sx , sy):
beta = alpha[na]
gam = alpha[na+1]
x = [] ; y = [] ;
r = 0.5*nc
x.append(r*np.cos(beta)) ; y.append(r*np.sin(beta)) ;
tt = np.linspace(beta,gam,10)
for i in range(len(tt)):
x.append(r*np.cos(tt[i]))
y.append(r*np.sin(tt[i]))
r-=0.5
x.append(r*np.cos(gam)) ; y.append(r*np.sin(gam))
tt = np.linspace(gam,beta,10)
for i in range(len(tt)):
x.append(r*np.cos(tt[i])) ; y.append(r*np.sin(tt[i]))
x = np.array(x) ; y = np.array(y)
verts = list(zip(x+sx,y+sy))
poly = Polygon(verts , facecolor=c , edgecolor=c)
ax.add_patch(poly)
#ppp(2,0,'r',0,0)
def get_coordiate(x , y):
beta = (alpha[y]+alpha[y+1])/2
pr = 0.5*(x+x-1)/2
sx = pr*np.cos(beta) ; sy = pr*np.sin(beta)
return sx,sy
def pp_arrow(x,y):
print x , y
sx , sy = get_coordiate(x, y)
for i in range(-1,2):
for j in range(-1,2):
if i == 0 and j == 0:
continue
ex , ey = get_coordiate(x+i, y+j)
ax.arrow(sx,sy,ex-sx,ey-sy,head_width=0.05,head_length=0.1,fc='r',ec='r')
def pxy(cx,cy):
for i in range(10):
plt.plot(0.5*i*np.cos(t)+cx,0.5*i*np.sin(t)+cy)
for i in range(len(alpha)):
plt.plot((0.5*np.cos(alpha)+cx,4.5*np.cos(alpha)+cx),(0.5*np.sin(alpha)+cy,4.5*np.sin(alpha)+cy))
cx = 13 ; cy =0
pxy(0,0)
pxy(13,0)
mr = np.zeros((10,30))
mb = np.zeros((10,30))
for i in range(3,9):
for j in range(1,27):
ttt = np.random.random()
if ttt >= 0.98 and ttt <= 1:
ppp(i,j,'r',0,0)
mr[i][j] = 1
continue
if ttt < 0.8:
continue
else:
ppp(i,j,'b',0,0)
mb[i][j] = 1
for i in range(10):
for j in range(30):
if mr[i][j] == 0:
continue
pp_arrow(i, j)
ma = 0 ;posx = 1 ; posy = 1
for k in range(-1,2):
for s in range(-1,2):
mb[i+k][j+s]=0
ttt = np.random.random()
if ttt > ma:
ma = ttt
posx = k ; posy = s
ppp(i+posx , j+posy , 'r' , 13 , 0)
ppp(i,j,'g',13,0)
for i in range(10):
for j in range(30):
if mb[i][j] == 0:
continue
ppp(i , j , 'b' , 13 , 0)
arrow = mpatches.Arrow(5, 0
,3,0,width = 1,color = 'r')
ax.add_patch(arrow)
ax.text(6.2,0.5,'after one\nunit time',ha='center',va='center',color='y')
xx = [4,4,4]
yy = [7.5,6.5,5.5]
c = ['b' , 'r' , 'g']
s = ['debris','satellite' , 'the location of satellite one unit time ago']
for i in range(3):
print xx[i] , yy[i]
rect = mpatches.Rectangle((xx[i],yy[i]),0.5,0.3,ec = c[i],fc=c[i] )
ax.text(xx[i]+0.7,yy[i],s[i])
ax.add_patch(rect)
plt.axis('off')
plt.show()读到这里，这篇“怎么实现python画圆功能”文章已经介绍完毕，想要掌握这篇文章的知识点还需要大家自己动手实践使用过才能领会，如果想了解更多相关内容的文章，欢迎关注创新互联行业资讯频道。
