13518219792
R/G/B值最小是0最大是255属Byte值类型
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Dim cr As Color = 控件.BackColor '获取控件背景色
Dim alpha As Byte = cr.A '透明度
Dim R As Byte = cr.R 'R值
Dim G As Byte = cr.G 'G值
Dim B As Byte = cr.B 'B值
Dim outAcr As Color = Color.FromArgb(alpha, R, G, B) '创建带有透明通道的ARGB颜色
Dim outcr As Color = Color.FromArgb(R, G, B) '创建不透明的RGB颜色
选中就是高亮，首先得到你找到的文本字符的起始位置和长度，然后
TextBox.Select(start,length)
或
TextBox.SelectionStart = start
TextBox.SelectionLength = length
也容易，如果是黑白三个颜色加上相同的渐变量，彩色的是起始颜色的三个分量与终止颜色的对应三个分量的差值，再除于相同的份数，就得出三原色各自的步进量。
窗体上放个图片框试试下面代码：
Private Sub PictureBox1_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles PictureBox1.Paint
Dim startColor As Color = Color.Red
Dim endColor As Color = Color.Green
Dim s As String = "vb.net 如何使文字能渐变颜色，就是颜色慢慢变淡然后在慢慢恢复？"
Dim Steps As Integer = s.Length \ 2
Dim StepR As Integer = (CInt(endColor.R) - startColor.R) \ Steps
Dim StepG As Integer = (CInt(endColor.G) - startColor.G) \ Steps
Dim StepB As Integer = (CInt(endColor.B) - startColor.B) \ Steps
Dim R As Integer = startColor.R
Dim G As Integer = startColor.G
Dim B As Integer = startColor.B
Dim drawFont As New System.Drawing.Font("Arial", 16)
Dim X As Integer = 50
For i As Integer = 1 To Steps
Dim drawBrush As New SolidBrush(Color.FromArgb(R, G, B))
e.Graphics.DrawString(s.Substring(i - 1, 1), drawFont, drawBrush, X, 50.0)
X += 18
R += StepR
G += StepG
B += StepB
Next
For i As Integer = 1 To Steps
Dim drawBrush As New SolidBrush(Color.FromArgb(R, G, B))
e.Graphics.DrawString(s.Substring(i + Steps - 1, 1), drawFont, drawBrush, X, 50.0)
X += 18
R -= StepR
G -= StepG
B -= StepB
Next
End Sub
css
可以控制按钮的外观
也有一些外置的类 去搜下 可以控制外观
of course.
搂主现在还在用VB6.0
都有VB.Net了
把Slider的值转换成Color，再付给窗体的BackColor就行了
