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java中怎么将xml转换成对象，相信很多没有经验的人对此束手无策，为此本文总结了问题出现的原因和解决方法，通过这篇文章希望你能解决这个问题。
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package util;
import lombok.extern.slf4j.Slf4j;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import java.io.File;
import java.io.FileInputStream;
import java.io.StringReader;
import java.io.StringWriter;
@Slf4j
public class JaxbUtil {
public static JAXBContext newInstance(Class obj) {
JAXBContext jaxbContext = null;
try {
jaxbContext = JAXBContext.newInstance(obj);
} catch (JAXBException e) {
e.printStackTrace();
}
return jaxbContext;
}
public static String convertToXml(Object obj) {
return convertToXml(obj, "UTF-8");
}
public static String convertToXml(Object obj, String encoding) {
String result = null;
try {
JAXBContext context = JAXBContext.newInstance(obj.getClass());
Marshaller marshaller = context.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(Marshaller.JAXB_ENCODING, encoding);
StringWriter writer = new StringWriter();
marshaller.marshal(obj, writer);
result = writer.toString();
} catch (Exception e) {
log.error("convertToXml error", e);
}
return result;
}
public static T converyToJavaBean(String xml, JAXBContext context) {
T t = null;
StringReader sr = null;
try {
sr = new StringReader(xml);
Unmarshaller unmarshaller = context.createUnmarshaller();
t = (T) unmarshaller.unmarshal(sr);
} catch (Exception e) {
log.error("converyToJavaBean error", e);
} finally {
if (null != sr) {
sr.close();
}
}
return t;
}
public static T xmlAnalyze(String path, JAXBContext jaxbContext, T t) {
try {
File file = new File(path);
FileInputStream in = new FileInputStream(file);
int size = in.available();
byte[] buffer = new byte[size];
in.read(buffer);
in.close();
String xmlStr = new String(buffer, "utf-8");
t = JaxbUtil.converyToJavaBean(xmlStr, jaxbContext);
} catch (Exception e) {
log.error("xml解析失败" + t.getClass());
}
return t;
}
// public static void main(String[] args) {
// OutInfo outInfo = new OutInfo();
// outInfo = xmlAnalyze("C:\\Users\\yzhang\\Desktop\\inout_pedinfo_8_000026600.xml", newInstance(outInfo.getClass()), outInfo);
// System.out.println(outInfo);
// }
} 看完上述内容，你们掌握java中怎么将xml转换成对象的方法了吗？如果还想学到更多技能或想了解更多相关内容，欢迎关注创新互联行业资讯频道，感谢各位的阅读！
