13518219792
VB 中如果要将 一个十进制数转换成十六进制进行输出，可以直接使用一个函数。例如，
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x=255
print hex$(x)
运行后就会得到输出为：FF
VB.NET控制台程序：
Module module3
Sub Main()
Dim i As Integer
Dim num As Integer = -35
Dim R As Integer = 8
Dim arr(33) As Integer
Dim len As Integer
arr = TransToR(num, R)
len = arr(0)
Console.Write(num " 转换成 " R " 进制后：" vbTab)
If (arr(1) = 1) Then
Console.Write("-")
End If
For i = len + 1 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToSourceCode(num)
Console.Write(num " 转换成32位二进制源码后：" vbTab)
Console.Write(arr(1))
For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToReverseCode(num)
Console.Write(num " 转换成32位二进制反码后：" vbTab)
Console.Write(arr(1))
For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
arr = TransToCompensatoryCode(num)
Console.Write(num " 转换成32位二进制补码后：" vbTab)
Console.Write(arr(1))
For i = 32 To 2 Step -1
Console.Write(arr(i))
Next
Console.WriteLine()
End Sub
'将十进制数num转换为R(2=R=9)进制数，结果存在arr数组中
'arr(0)存储长度, arr(1)存储符号位：1为负，0为正
Function TransToR(ByVal num As Integer, ByVal R As Integer) As Integer()
Dim arr(33) As Integer
arr(0) = 0 '初始长度
'设置符号位
If (num 0) Then
arr(1) = 1
Else
arr(1) = 0
End If
num = Math.Abs(num)
While num 0
arr(0) = arr(0) + 1
arr(arr(0) + 1) = num Mod R
num \= R
End While
Return arr
End Function
'将十进制数num转换为二进制原码
Function TransToSourceCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
arr = TransToR(num, 2)
'高位补零
For i = arr(0) + 2 To 32
arr(i) = 0
Next
arr(0) = 32
Return arr
End Function
'将十进制数num转换为二进制反码
Function TransToReverseCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
arr = TransToSourceCode(num)
If num = 0 Then
Return arr
End If
'除符号位外各位取反
For i = 2 To 33
arr(i) = 1 - arr(i)
Next
Return arr
End Function
'将十进制数num转换为二进制补码
Function TransToCompensatoryCode(ByVal num As Integer) As Integer()
Dim arr(33) As Integer
Dim i As Integer
Dim c As Integer = 0 '进位
arr = TransToReverseCode(num)
If num = 0 Then
Return arr
End If
'末尾加1
i = 2
arr(i) += 1
Do While True
arr(i) = c + arr(i)
c = arr(i) \ 2
arr(i) = arr(i) Mod 2
i += 1
If c 1 Then
Exit Do
End If
Loop
Return arr
End Function
End Module
'此函数用于十进制到二进制
Private Function Bin(Number As Long) As Long
Dim Div_value As String
Do
Div_value = (Number Mod 2) Div_value
Number = Int(Number / 2)
Loop Until Number 2
Bin = Number Div_value
End Function
'此函数用于二进制到十进制
Private Function value_Bin(Number As Long) As Long
Dim Temp_value As Long, Cyc As Long
For Cyc = 0 To Len(Str(Number))
If Cyc = Len(Str(Number)) Then
value_Bin = Temp_value + Val(Mid(Str(Number), Cyc, 1))
Exit For
End If
If Cyc 0 Then Temp_value = (Temp_value + Val(Mid(Str(Number), Cyc, 1))) * 2
Next Cyc
End Function
'====写入以上函数后转值操作：
'十进制到十六进制：Hex(十进制数值)
'十进制到八进制：Oct(十进制数值)
'十进制到二进制：Bin(十进制数值)
'二进制到十进制：value_Bin(二进制数值)
'八进制到十进制：Val("O" 八进制数值)
'十六进制到十进制：Val("H" 十六进制数值)
比如
msgbox DEC_to_BIN(10)
就会返回一个10转换为十进制后的结果
或者简单点就用
VB自带函数：
十进制转八进制：Oct(num)
十六进制转八进制：oct("H" num)
十进制转十六进制：hex(num)
八进制转十六进制：hex("O" num)
十六进制转换为十进制
Dim str As String
str = Text2.Text
Text10.Text = CLng("H" str)
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
MsgBox(DEC_to_HEX(255))
End Sub
Public Function DEC_to_HEX(ByVal Dec As Long) As String
Dim a As String
DEC_to_HEX = ""
Do While Dec 0
a = CStr(Dec Mod 16)
Select Case a
Case "10" : a = "A"
Case "11" : a = "B"
Case "12" : a = "C"
Case "13" : a = "D"
Case "14" : a = "E"
Case "15" : a = "F"
End Select
DEC_to_HEX = a DEC_to_HEX
Dec = Dec \ 16
Loop
End Function
